Today, we'll move from the cold atomic (HI) phase of the ISM to the cold molecular (H2) phase.
Table 1 taken from
Ferriere, K. M., Reviews of Modern Physics, 73, 1031 (2001)
As you will see shortly, clouds of gas in molecular form aren't just hydrogen; there are a number of heavier elements which play important roles in their creation. Sometimes, the trace elements can help us to study the clouds; other times, they just get in our way.
So, let's review the abundances of the elements in space. There are variations from place to place, and from long ago until recent times, but the graph below, based on observations in the Solar System, provides a useful general guide. Pay special attention to the labels on the Y-axis.
Clouds of cold atomic hydrogen are easy to find,
since the atoms emit radio waves at a wavelength
of 21 cm due to the hyperfine transition in the ground state.
What about cold molecular hydrogen gas?
What sort of radiation does it emit?
Alas, molecules of hydrogen do not radiate electromagnetic
energy very efficiently.
The problem is that the coupling between a molecule
and the electromagnetic field --
which determines the probability that photons will be
absorbed or emitted by the molecule --
depends in large part on the electric dipole moment
of the molecule.
The stronger the dipole moment, the more strongly
the molecule interacts with electromagnetic radiation.
Molecular hydrogen consists of two identical atoms joined together,
yielding no electric dipole moment at all.
The combination does have a quadrupole moment,
but that yields only weak coupling to photons.
In order to detect clouds of molecular gas, we need to look
for OTHER molecules,
preferably those which
Among the best options are
though radio astronomers have
found many others
(thanks to
Karen Lee-Waddell's ICRAR/CASS Radio School 2018 presentation.)
We will concentrate on the carbon monoxide molecule for
the rest of today's discussion.
Inside clouds of molecular gas,
the temperatures are very low, only 10 - 20 Kelvin.
That means that only transitions between very low energy states
are likely to produce significant amounts of radiation.
Instead of considering the
electronic energy states of these molecules,
we should instead examine the
vibrational
and
rotational
energy states.
Let's start with VIBRATIONAL modes.
You should remember the example of a block attached
to a spring, sliding along a frictionless floor.
If one pulls the block away from its rest position,
it will start to oscillate back and forth
in Simple Harmonic Motion (SHM).
The mass m of the block and the force constant k
of the spring, of course.
One can build a similar model of a CO molecule as two
masses attached by a spring:
Unlike the everyday block and spring,
this molecule can oscillate at a number of different frequencies.
A quantum mechanical analysis shows that
the allowed frequencies follow a simple pattern
(at least for the lowest energy states,
which are the relevant ones inside a molecular cloud).
The corresponding vibrational energies of the molecule
are
In the case of CO,
the combination ℏω0
is equal to
0.269 eV.
One of the strongest lines emitted by the molecule
involves a transition from
the vibrational state n = 1 to the ground state n = 0.
There is a second way that molecules can produce
(or absorb) electromagnetic radiation:
by making transitions between ROTATIONAL states.
Just as the vibrational states of these molecules
are quantized,
so are their rotational states:
molecules may only have specific values of rotational angular momentum.
As a result, their rotational energies are also quantized.
One can express these rotational energy states as
where J is the rotational quantum number.
It is common to replace the ℏ/2I term
with a single constant B0 for convenience,
yielding
One can look up the rotational energy constant B0
for any particular molecule of interest.
In the case of CO,
it has value
B0 = 2.3825 x 10-4 eV.
In the case of rotational transitions,
quantum mechanical rules require that the rotational index J
changes by one;
in other words,
J → J ± 1.
Radio astronomers have adopted CO as a tracer
of molecular hydrogen:
if they detect CO in some region of space, they can assume safely
that molecular hydrogen is there, too.
But because both carbon and oxygen are less common in the ISM
than hydrogen,
the number of
H2 molecules
will greatly exceed that of CO.
As a rough guide,
one can expect roughly
20,000 molecules of H2 for every single CO.
One might think that since hydrogen atoms are by far the
most common denizens of space,
the creation of hydrogen molecules would be a simple matter:
whenever two H atoms bump into each other,
they stick together and *poof* an H2 molecule is formed.
Alas, no. The probability that two H atoms will actually
combine during a collision is very, very, very small.
While this can happen, and was the mechanism for creating
molecular gas in the very early universe,
it's just too slow to be important in the contemporary Milky Way.
Instead, the dominant mechanism for the creation of molecular hydrogen
involves a catalyst:
dust grains.
The basic idea is that
a grain provides a place for hydrogen atoms to meet and form pairs --
sort of like a celestial singles bar.
The sequence of events runs like so:
One of the reasons that this process is so efficient is that,
under typical conditions in a molecular cloud,
collisions between dust grains and H atoms are pretty frequent,
providing many opportunities for molecules to form.
How frequent are the collisions?
Let's do a quick estimate.
In a typical atomic cloud, the gas has
Dust grains (which we will discuss in detail shortly) have a wide range
of properties, but a representative grain might have a radius
of about a = 0.1 micron = 10-7 m.
We'll talk more about dust in a week or two,
but here's a quick introduction.
Scientists don't have to rely upon theory and
remote observations to figure out the properties of
interstellar dust grains (though they do use these tools),
because we have been able to collect some
actual grains and bring them to labs on Earth.
Objects in space will always encounter the Earth
with a large relative speed;
recall that the Earth's orbital velocity is about 29 km/s,
and other objects in the Solar System
will move with similar speeds.
When a large object --
such as whole asteroids or fragmented "rocks"
created in collisions between asteroids --
encounters the Earth,
it maintains its speed as it pushes through the air violently.
We call the brief flashes of light caused by the heated
gas surrounding the object a meteor.
Smaller objects, however,
may have a much more gentle ride.
Grains of dust can be small enough that just a few
collisions with air molecules dissipate most of
their relative speed,
allowing them to float aimlessly in the
upper atmosphere in the same way that
pollen and volcanic dust particles sometimes do.
One can simply spread out a white sheet on the ground
on a windless summer day, wait for a few hours,
and find some interplanetary material among the
ordinary fluff.
Or, if one is in a hurry,
one can fly up into the upper reaches of the atmosphere
and grab them in situ.
The picture below shows a grain of dust collected
by a high-flying aircraft several decades ago.
Chemical analysis of these grains reveals that some
have extra-terrestrial origins.
Some NASA spacecraft have also collected tiny specks
of material
at different locations in the Solar System
and returned them to Earth.
The pictures below show material gathered by the Stardust mission.
Figure courtesy of
MHz`as and Wikipedia ,
based on data in
Lodders, K., ApJ 591, 1220 (2003)
Q: How many hydrogen atoms are there for every single carbon atom?
Q: Do you notice a pattern in these abundances? Can you explain it?
Q: Why is the value for hydrogen set to 12?
My answers.
It's not so easy to see molecular H2
Diagram of electric dipole courtesy of
Geek3
and
Wikimedia.
Q: Can you think of any molecules which might meet these conditions?
Q: What determines the frequency of this oscillation?
Q: What is the energy of a photon produced by this transition?
Q: What is the wavelength of the photon?
Q: In what region of the electromagnetic spectrum does this line appear?
My answers.
Q: Compare the constants in front of the expressions for energy
states in vibrational and rotational states for CO.
vibrational: E(n) = 0.269 eV * (n + 1/2)
rotational: E(J) = 0.00023825 eV * [ J(J+1) ]
Which type of transition requires the molecules to have
higher energies?
Q: Compute the energy of a photon emitted when a CO molecule
drops from J = 1 to J = 0.
Q: What is the wavelength of this photon?
My answers.
The role of dust in the creation of molecular hydrogen
Figure 7.4 from
Ryden and Pogge, "Interstellar and Intergalactic Medium", Cambridge (2021) ,
after the original Fig 1 of
Delieu et al., Scientific Reports, 3, 1338 (2013)
Q: What is the typical speed of hydrogen atoms?
Q: What is the mean free path of a dust grain?
Q: How long between each collision of an H atom and the grain?
My answers.
Dust particle collected by U2 aircraft,
courtesy of
NASA
Figure 3 (panels A, B) taken from
Ishii, H. A., et al., Science, 319, 447 (2008)
Image courtesy of
NASA, ESA, Hubble Space Telescope Orion Treasury Project Team, Massimo Robberto (STScI, ESA); Image Processing: Zoltan Levay (STScI), Joseph DePasquale (STScI)
Image courtesy of
NASA, ESA, CSA, PDRs4ALL ERS Team, Jason Champion (CNRS), Pam Jeffries (STScI)
Chandra image of G292.0+1.8 courtesy of
NASA/CXC/UCSC/L. Lopez et al.
Table 4 from
Bhalerao, J., Park, S., and Schenck, A., ApJ 872, 31 (2019)
Image of M57 courtesy of
NASA, ESA and the Hubble Heritage (STScI/AURA)-ESA/Hubble Collaboration
Infrared image of M57 courtesy of
ESA/Webb, NASA, CSA, M. Barlow (UCL), N. Cox (ACRI-ST), R. Wesson (Cardiff University)
Image of RCW 58 courtesy of
Mike Selby & Mark Hanson and Astronomy Picture of the Day
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Copyright © Michael Richmond.
This work is licensed under a Creative Commons License.