P^{2} = \frac{4π^{2}}{G(m_{1} + m_{2})} a^{3}

spindown timescale T = \frac{P}{Ṗ} = \frac{P}{dP/dt}

Period P = 0.089218 s

\frac{dP}{dt} = \frac{4.38 × 10^{−5} s}{3.456 × 10^{8} s} = 1.267 × 10^{−13}

T = \frac{0.089218 s}{1.267 × 10^{−13}} = 7.0 × 10^{11} s = 22, 000 yr