Copyright © Michael Richmond.
This work is licensed under a Creative Commons License.
Question 1
Electric field is E = (3, 0, 0) N/C everywhere. What is the potential difference V(B) - V(A) if
A = (1, 1, 1) m
B = (2, 2, 2) m
Answer: To find the potential difference, integrate the electric
field over a path from A to B:
B
/
V(B) - V(A) = - | E dot ds
/
A
Recall that 3 N/C = 3 V/m.
= - E * x evalulated from A to B
= - [ (3 V/m * 2 m) - (3 V/m * 1 m) ]
= - [ 6 V/m - 3 V/m ]
= - 3 Volts
Question 2
Electric potential is V = 6 Volts everywhere. What is the electric field at point A = (1, 1, 1) m?
Answer: Electric field is gradient of electric potential
Ex = dV/dx = 0
Ey = dV/dy = 0
Ez = dV/dz = 0
Question 3
Electric field of strength 6 N/C can be written equivalently as ...
Answer: 6 V/m, because 1 Newton/Coulomb is the same as 1 Volt/meter
Copyright © Michael Richmond.
This work is licensed under a Creative Commons License.