Creative Commons License Copyright © Michael Richmond. This work is licensed under a Creative Commons License.

Rotational KE and work

You remember the relationship between the change in Kinetic Energy of an object and the Work done by forces on it, right?

For example,



A chunk of ice of mass m = 2 kg sits motionless on a frictionless frozen pond. Then a breeze starts to push the ice cube with a constant force F = 3 N. After the chunk has slid 50 m, how fast is it going?


Well, there are very similar relationships between the angular analogues of these quantities: the change in rotational KE of an object and the Work done on it by torques.

For example,



A giant grindstone with radius r = 2 m and moment of inertia I = 700 kg*m^2 is spinning at 10 rpm. Joe slows it down by pressing a wooden brake against the rim of the wheel. How much torque must he exert in order to stop it within 5 revolutions?

How hard must Joe press the brake against the rim of the wheel to cause this to happen?




Creative Commons License Copyright © Michael Richmond. This work is licensed under a Creative Commons License.