Joe feels the wall pressing against his back. How strong is this normal force?
Answer: The normal force provides the push to keep Joe moving in uniform circular motion. It thus provides the centripetal force m v^2 F = ------ R Here, room has radius R = 3 m, and circumference C = 2 pi R = 18.8 meters. The room makes on revolution in T = 2 seconds, and Joe spins with speed C 18.8 m v = ----- = ------ = 9.4 m/s T 2 s Therefore, the centripetal force is m v^2 (60 kg) * (9.4 m/s)^2 F = ------ = ----------------------- R 3 m = 1770 N
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