Copyright © Michael Richmond.
This work is licensed under a Creative Commons License.
Joe feels the wall pressing against his back. How strong is this normal force?
Answer: The normal force provides the push to keep Joe moving in
uniform circular motion. It thus provides the centripetal
force
m v^2
F = ------
R
Here, room has radius R = 3 m, and circumference
C = 2 pi R = 18.8 meters. The room makes on revolution
in T = 2 seconds, and Joe spins with speed
C 18.8 m
v = ----- = ------ = 9.4 m/s
T 2 s
Therefore, the centripetal force is
m v^2 (60 kg) * (9.4 m/s)^2
F = ------ = -----------------------
R 3 m
= 1770 N
Copyright © Michael Richmond.
This work is licensed under a Creative Commons License.